X^2-9x-486=0

Solution for X^2-9x-486=0 equation:

X^2-9X-486=0

a = 1; b = -9; c = -486;
Δ = b2-4ac
Δ = -92-4·1·(-486)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-45}{2*1}=\frac{-36}{2}
=-18
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+45}{2*1}=\frac{54}{2}
=27
$